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14v^2+7v-70=0
a = 14; b = 7; c = -70;
Δ = b2-4ac
Δ = 72-4·14·(-70)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-63}{2*14}=\frac{-70}{28} =-2+1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+63}{2*14}=\frac{56}{28} =2 $
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